Question

Решите уравнения:
2x^2-9x+10=0


5x^2+3x-8=0

Answer 1

$2 x^{2} -9x+10=0 \ D=81-4*2*10=1 \ x_{1} = (9-1)/2*2=2 \ x_{2} =(9+1)/4=2.5 \ \ 5 x^{2} +3x-8=0 \ D=9-4*5*(-8)=169 \ x_{1} =(-3-13)/10=-1.6 \ x_{2} =(-3+13)/10=1$