Question

решите методом алгебраического сложения .
3х-3у=2
-2х-4у=1

Answer 1

$left { {{3x-3y=2} atop {-2x-4y=1}} right. left { {{6x-6y=4} atop {-6x-12y=3}} right. left { {{6x-6y=4} atop {-18y=7}} right. left { {{6x-6y=4} atop {y=- frac{7}{18} }} right.$

$left { {{6x=4+6y} atop {y=- frac{7}{18} }} right. left { {{6x=4-6* frac{7}{18} } atop {y=- frac{7}{18} }} right. left { {{6x=4- frac{7}{3} } atop {y=- frac{7}{18} }} right. left { {{x= frac{4}{6} - frac{7}{18} } atop {y=- frac{7}{18} }} right. left { {{x= frac{12}{18} - frac{7}{18} } atop {y=- frac{7}{18} }} right. left { {{x= frac{5}{18}} atop {y=- frac{7}{18} }} right.$