Question

помагите пж
16c²-49=0
64x²-25=0

Answer 1

$16c^2 - 49 = 0 (4c - 7)(4c + 7) = 0 4c - 7 = 0 ; 4c + 7 = 0 c1 = 7/4 ; c2 = -7/4 c1 = 1,75 ; c2 = -1,75$

$64x^2 - 25 = 0 (8x - 5)(8x + 5) = 0 8x - 5 = 0 ; 8x + 5 = 0 x1 = 5/8 ; x2 = -5/8 x1 = 0,625 ; x2 = -0,625$

Answer 2

спс

Answer 3

http://znanija.com/task/15508999 реши это пж