Question

помогите пжл решить все

Answer 1

1. $sqrt{35} textless 6 \ 5 sqrt{6} textgreater 4 sqrt{7}$
2. $= 0,4 sqrt{2500} + 13 = 0,4*50 + 13 = 33$
$= sqrt{6*4} - 4 sqrt{6} + sqrt{9*6} = 2 sqrt{6 } - 4 sqrt{6} + 3 sqrt{6} = sqrt{6}$
3. $= ( 3^{2} - ( sqrt{7}) ^{2}) = 9 - 7 = 2$
$= 3( sqrt{2} ) ^{2} + sqrt{50*2} = 3*2 +10= 16$
$= 6^{2} - 12sqrt{3} + ( sqrt{3} ) ^{2} = 36 - 12 sqrt{3} +3 = 39 - 12 sqrt{3}$
$= 10 sqrt{3} - 4 sqrt{16*3} - sqrt{25*3} = 10 sqrt{3} - 16 sqrt{3} - 5 sqrt{3}= - 11 sqrt{3}$
4. $= frac{(2- sqrt{c})(2+ sqrt{c)} } { sqrt{c} (2+ sqrt{c)} } = frac{(2- sqrt{c)}} { sqrt{c} } = frac{ sqrt{c}(2- sqrt{c)} } {(sqrt{c} )^{2} } = frac{2 sqrt{c} - c } {c}$
5. $= frac{4(3- sqrt{15)} + 4( 3+ sqrt{15} ) } {3 ^{2} - ( sqrt{15} ^{2} ) } = frac{12 - 4 sqrt{15} + 12 + 4 sqrt{15} } {3 ^{2} - ( sqrt{15}) ^{2} } = frac{24} {9 - 15} = frac{24} {-6} = -4$