Question

1) y= sin^4 (5x-3tgx) / y'=?
2) {2x+y=3
{5x-z=4
{-3y-2z=-5

Answer 1

1
$y`=4sin^3(5x-3tgx)*cos(5x-3tgx)*(5-3/cos^2x)$
2
{2x+y=3⇒y=3-2x
{5x-z=4⇒z=5x-4
{-3y-2z=-5
-3(3-2x)-2(5x-4)=-5
-9+6x-10x+8=-5
-4x=-5+1
-4x=-4
x=1
y=3-2=1
z=5-4=1
(1;1;1)