Question

(Х+3)квадрат=2Х+6
(Х+2)квадрат=43-6Х
можете решить эти 2,прошу :3

Answer 1

$(x+3)^2 = 2x+6 -6 - 2x + (x+3)^2 = 0 x^2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x1 = -1 ; x2 = - 3$

$(x+2)^2 = 43-6x -43 + 6x + (x+2)^2 = 0 x^2 + 10x - 39 = 0 (x - 3)(x + 13) = 0 x1 = 3 ; x2 = -13$

Answer 2

(x+3)^2=2x+6
x^2+6x+9=2x+6
x^2+4x+3=0
D=16-12=4;2
x1=((-4)+2)/2=-1
x2=((-4)-2)/2=-3