Question

решите уравнение
y^2-4=0
1,96-y^2=0

Answer 1

$y^2 - 4 = 0 (y - 2)(y + 2) = 0 y - 2 = 0 , y + 2 = 0 y1 = 2 ; y2 = -2$

$1,96 - y^2 = 0$
$frac{49}{25} - y^2 = 0$
$- frac{1}{25} (5y - 7)(5y + 7) = 0 5y - 7 = 0 ; 5y + 7 = 0 y1 = 7/5 , y2 = -7/5$
$y1 = 1,4 , y2 = -1,4$