Question

tg pi(2x-3)/4=- корень из 3

Answer 1

tg(π(2x-3)/4)=-√3
π(2x-3)/4=arctg(-√3)+πn, n∈Z
π(2x-3)/4=-arctg√3+πn, n∈Z
π(2x-3)/4=-π/3+πn, n∈Z |*4
π(2x-3)=-4π/3+4πn, n∈Z |:π
2x-3=-4/3+4n, n∈Z
x=(-4/3+3):2+4n/2, n∈Z
x=5/6+2n, n∈Z