Question

х(4х+11)-7(х^2-5х)=-3х(х+3)

Answer 1

$x(4x + 11) - 7(x^2 - 5x) = -3x(x+3) 46x - 3x^2 = -3x(x + 3) 46x - 3x^2 = -9x - 3x^2 46x - 3x^2 + 9x + 3x^2 = 0$
$55x = 0 |:55$
$x = 0$

Answer 2

х(4х+11)-7(х²-5х)=-3х(х+3)
4х²+11х-7х²+35х+3х²+9х=0
55х=0
х=0
ответ: 0