Question

25^log(5)3)+0.04^log (0.2)8)-9^log(81)4)

Answer 1

$25^{log_{5} 3 } + 0.04^{log _{0.2} 8} - 9^{log _{81}4 } = 5^{log _{5} 9} + 0.2^{log _{0.2}64 }- 9^{log _{9}2 } =$ 
= 9+64-2=71

Answer 2

---------------ответ: 71