Question

sin2x / sin (3п/2-x ) =√2

Answer 1

sin2x/sin(3π/2 -x) =√2 ;
* * *sin2x =2sinxcosx ; sin(3π/2 -x) = - cosx  * * *
2sinxcosx/(-cosx) = √2 ;
sinx = -(√2)/2 ;
x =( -1) ^(n+1)*π/4 +π*n , n∈Z.