Question

lim x стремится к 0
1- cos6x/2xtg2x

Answer 1

$lim_{x to 0} frac{1-cos 6x}{2x{rm tg},2x} = lim_{x to 0} frac{sin^2 3x}{2x{rm tg},2x}= lim_{x to 0} frac{sin^2 3x}{9x^2} frac{2x}{{rm tg},2x} frac{9}{4}=frac{9}{4}$