Question

arccos (-корень3/2) + arcsin(-корень3/2)

Answer 1

$arccos(- frac{ sqrt{3} }{2} )+arcsin(- frac{ sqrt{3} }{2} )= \ \ = pi -arccos frac{ sqrt{3} }{2}-arcsin frac{ sqrt{3} }{2} = \ \ = pi - frac{ pi }{6}- frac{ pi }{3}= frac{6 pi - pi -2 pi }{6}= frac{3 pi }{6}= frac{ pi }{2}$