Question

(х+4)^2-(х-2)(х+2)=0

Answer 1

( x + 4)² - ( x - 2)( x + 2)= 0
x² + 8x + 16 - ( x² - 4) = 0
x² - x² + 8x + 20 = 0
8x = - 20
x= - 20/8
x = - 2,5

Answer 2

можете остальное решить

Answer 3

(2х-5)²-(2х-3)(2х+3)=0

Answer 4

(3х+5)(3х-5)-(3х-1)²=10

Answer 5

2(2х+1)²-8(х+1)(х-1)=34

Answer 6

пожалуйста