Question

3 (sin 10 + sin 80)(cos 80-cos 10)/2 sin 70

Answer 1

$\frac{3(sin10+sin80)(cos80-cos10)}{2sin70}=\frac{3(sin10+sin(90-10))(cos(90-10)-cos10)}{2sin(90-20)}=\\ \frac{3(sin10+cos10)(sin10-cos10)}{2cos20}=\frac{3(sin^210-cos^210)}{2cos20}=\frac{-3cos(2*10)}{2cos20}=\\-\frac{3cos20}{2cos20}=- \frac{3}{2}$