Question

2 задание!!!!)))))))))))

Answer 1

$y^2-10y+24=0$
$D_1=( \frac{b}{2} )^2-ac$
$D_1=( \frac{-10}{2} )^2-1*24=25-24=1$
$x_1=- \frac{-10}{2}+ \sqrt{1} =5+1=6$
$x_2=- \frac{-10}{2}- \sqrt{1}=5-1=4$


$\left \{ {{x=10-4} \atop {y=4}} \right. \left \{ {{x=6} \atop {y=4}} \right. or \left \{ {{x=10-6} \atop {y=6}} \right. \left \{ {{x=4} \atop {y=6}} \right.$