Question

Решите уравнение:
8y^2-3y=0
10t^2+2t=0

Answer 1

8y^2 - 3y = 0 
y (8y - 3) = 0

y = 0 ;
8y - 3 = 0 ==> 8y = 3 ==> y = 3/8 = 0,375

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10t^2 + 2t = 0 
t( 10t + 2) = 0 

t = 0 ;
10t + 2 = 0 ==> 10t = - 2 ==> t = - 2/10 = - 0,2

Answer 2

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