Question

(x^2+3)^2=(x^2-3)(x^2+3)+6(x^2+3)

Answer 1

$(x^2+3)^2=(x^2-3)(x^2+3)+6(x^2+3)$

$x^4 + 6x^2 + 9 = x^4 - 9 + 6x^2 + 18$

$0 = 0$