Question

4,5 ЗАДАНИЯ
СРОЧНОООО!!!!!!!!!

Answer 1

$4. \\ a) x^{2} -x = 0 \\ x(x-1)=0 \\ x=0 или x=1 \\ b) \frac{x+3}{4} - \frac{x}{2} =3 \\ 2(x+3)-4x=24 \\ 2x+6-4x=24 \\ -2x=18 \\ x=-9 \\ a) x^2+x=0 \\ x(x+1)=0 \\ x=0 или x=-1 \\ b) \frac{x-2}{6} - \frac{x}{2} = 2 \\ 2(x-2)-6x=24 \\ 2x-4-6x=24 \\ -4x=28 \\ x=-7 \\ 5. \\ 2a-b=5 \\ 4a-2b=2(2a-b) =\ \textgreater \ 2*5=10 =\ \textgreater \ 4a-2b=10 \\ 6a-3b = 3(2a-b) =\ \textgreater \ 3*5=15$