Question

(b-2)²+2b(5+2) при b=√2

Answer 1

$(b-2)^2+2b(5+2) = b^2-4b+4+20b=b^2+16b+4 \\ b= \sqrt{2} \\ ( \sqrt{2)}^2 +16* \sqrt{2} +4 = 2+16 \sqrt{2} +4 = 6+16 \sqrt{2}$