Question

(x^2+3^x +3)^5 > (x^2+9^x -3^x)^5

Answer 1

$(x^2+3^x +3)^5 > (x^2+9^x -3^x)^5\ x^2+3^x +3 > x^2+9^x -3^x\ -9^x+2*3^x+3>0\ 3^x=a\ -a^2+2a+3>0\ (a+1)(a-3)<0\ -1<3^x<3\ x<1$

(- ∞; 1)