Question

(Х-5)(х+5)=х(5-х) решить уравнение

Answer 1

$x^{2}$-25=5x-$x^{2}$
$x^{2}$-25-5x+$x^{2}$=0
2$x^{2}$-5x-25=0

$frac{5 frac{+}{-} sqrt{25-4*2*(-25)} }{2*2} = frac{5 frac{+}{-}15 }{4}$

x1 = $frac{5-15}{4} = - frac{10}{4} = - frac{5}{2} = - 2 frac{1}{2}$

x2= $frac{5+15}{4} = 5$