Question

вычислите f '(-2), если $f(x)=(5x+8)^{3}-2tg^{5}frac{pi}{5}$

Answer 1

f`=5*3*(5x+8)^2-2**0=15*(5x+8)^2

f '(-2)=15*(-10+8)^2=15*4=60

Answer 2

$f`=5*3*(5x+8)^2-2**0=15*(5x+8)^2 </var></p> <p><var>f '(-2)=15*(-10+8)^2=15*4=60$