Question

ax^2+bx^2-bx-ax+cx^2-cx

Answer 1

аx^2+bx^2-bx-ax+cx^2-cx=(аx^2+bx^2+cx^2)-cx-bx-ax =x^2(a+b+c)-x(c+b+a)=(a+b+c)(x^2-x)=(a+b+c)*x*(x-1)