Question

Преобразуйте в многочлен стандартного вида:
1) (5х+2)²
2) (1/3а²-1/9)²
3) (х-5у)²-(2х+у)²
4) (4х-3)²
5) (1/3а²+1/5)²
6) (5х+у)²-(х-2у)²

Answer 1

1) (5х+2)²=25x^2+10x+4
2) (1/3а²-1/9)²=1/9 a^4-2/27 a^2+1/81
3) (х-5у)²-(2х+у)²=(x-5y-2x-y)(x-5y+2x+y)=(-x-6y)(3x-4y)
4) (4х-3)²=16x^2-24x+9
5) (1/3а²+1/5)²=1/9 a^4+1/15a^2+1/25
6) (5х+у)²-(х-2у)²=(5x+y-x+2y)(5x+y+x-2y)=(4x+3y)(6x-y)