Question

найдите корни уравнения: а) (х-1)(х+2)(х+10)=0
б) 36-x^2=0
в) 5x=-20x
г) 8x-4x^2=0
д) x^2=8
е) (x-2)(x+3)=-6

Answer 1

a) ( x - 1)(x+ 2)(x+ 10) = 0
Произведение равно 0,когда один из множителей равен0,значит,
x - 1 = 0
x = 1
x + 2 = 0
x = - 2
x + 10 = 0
x = - 10

б) - x² = - 36
x² = 36
x = 6
x = - 6

в) 5x = - 20x
5x + 20x = 0
25x = 0
x = 0

г) - 4x² + 8x = 0
4x² - 8x = 0
4x(x - 2) = 0
4x = 0
x = 0
x - 2 = 0
x = 2

д) x² = 8
x = √8 = 2√2
x = - √8 = - 2√2

е) (x - 2)(x + 3) = - 6
x² + x - 6 + 6 = 0
x² + x = 0
x( x + 1) = 0
x = 0
x + 1 = 0
x = - 1