Question

Сократите дробь: (n+1)! / (n+3)!

Answer 1

(n+3)!=1*2*...*(n+1)*(n+2)*(n+3)=(n+1)!*(n+2)(n+3)

 

$dfrac{(n+1)!}{(n+3)!} = dfrac1{(n+2)(n+3)}$