Question

sin2x+3 = 3 sinx + 3 cosx.

Answer 1

$sin2x+3 = 3 sinx + 3 cosx\ sin^22x+6sin2x+9=9+9sin2x\ sin^22x-3sin2x=0\ sin2x=0 sin2x=3\ 2x=pi n xin varnothing\ x=(pi/2) n$