Question

Помогите пожалуйста номер 1 .

Answer 1

Решение
а)  log₅ 75 - log₅ 9 + log₅ 15 = log₅ [(75*15)/9] = log₅ 125 = log₅ 5³ = 3*log₅ 5 = 3
б)  [8^(1/3 + log₂ 3] : log₂ log₃ 81 = [8¹/³ * 2^(3*log₂ 3)] : log₂ log₃ 3⁴ =
= [2 * 2^(log₂ 3³)] : log₂ 4 log₂ 2 = (2 * 27) : log₂ 2² = 54 : 2 = 27