Question

log7(x-1)+log7(x-2)=log7(x+2)

Answer 1

ОДЗ
x>1,x>2,x>-2
x∈(2;∞)
log(7)(x-1)(x-2)=lof(7)(x+2)
x²-3x+2=x+2
x²-4x=0
x(x-4)=0
x=0 ∉ОДЗ
х=4