Question

решите уравнение: (x+4)*(x-3)+(x-5)*(x+4)=0

Answer 1

x^2-3x+4x-12+x^2+4x-5x-20

2x^2-32=0

x^2=16

x= -4;4

 

 

 

 

 

Answer 2

(x+4)*(x-3)+(x-5)*(x+4)=0

x^2-3x+4x-12+x^2+4x-5x-20=0

2x^2-32=0

x^2=32

x^2=32:2

x^2=16

x1=4

x2=-4