Question

sin2x+tgx=0 Помогите решить

Answer 1

sin2x-tg x=0
sinx•(2cosx-1/cosx)=0
1) sinx=0  =>  x=πn
2) 2cos²x-1=0  =>  cosx=±1/√2  =>  x₁=±π/4+2πn, x₂=π±π/4+2πn
x=π/4+(π/2)•n