Question

x^2-3/(x-2)(x-4)+x/2x-4=(2,5x-6)/(x^2-6x+8)

Answer 1

(x²-3)/((x-2)(x-4))+x/(2x-4)=(2,5x-6)/(x²-6x+8)
(x²-3)/((x-2)(x-4))+x/(2*(x-2))=(2,5x-6)/((x-2)(x-4))
ОДЗ: x-2≠0   x₁≠2   x-4≠=   x₂≠4
2*(x²-3)+x*(x-4)=2*(2,5x-6)
2x²-6+x²-4x-5x+12=0
3x²-9x+6=0    I÷3
x²-3x+2=0   D=1
x₁=1   x₂=2   x₂∉ОДЗ
Ответ: х=1.