Question

Решить систему уравнений

х^2 + у^2 = 10
х - у = 2.

Answer 1

$left { {{x^2+y^2= 10} atop {x-y = 2}} right. left { {{x^2+y^2= 10} atop {x=2-y}} right. left { {{(2-y)^2+y^2=10} atop {x=2-y}} right. \ (2-y)^2+y^2=10 \ y= (-1;3) \ x=2-(-1) \ x= 3 \ x=2-3 \ x= -1 \ x=3 \ y=-1$