Question

(2x-1)²-4(x-2)(x+2)=0

Answer 1

4x²-4x+1-4x²+16=0
4x=17
x=17/4
x=4,25

Answer 2

(2x-1)^2 - 4(x-2)(x+2) = 0 (4x^2 - 4x + 1) - 4(x-2)(x+2) = 0 4x^2 - 4x + 1 - 4(x^2 - 4) = 0 4x^2- 4x + 1 - 4x^2 + 16 = 0 - 4x + 17= 0 x = 17/4 = 4.25