Question

(2q-2)^2 , (4х+y)^2 помогите

Answer 1

1) (2q-2)^2= (2q)^2-2q*2*2+2^2=4q^2-8q+4

2)(4x+y)^2=(4x)^2-2*4xy+y^2=16x^2-8xy+y^2