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Answer 1

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Answer 2

$(frac{a+b}{a-b}+frac{a-b}{a+b}):(frac{a^2}{a^2-b^2}+frac{1}{frac{a^2}{b^2}-1})=frac{(a+b)^2+(a-b)^2}{(a+b)(a-b)}:(frac{a^2}{a^2-b^2}+frac{1}{frac{a^2-b^2}{b^2}})=$

$frac{a^2+2ab+b^2+a^2-2ab+b^2}{(a+b)(a-b)}:(frac{a^2}{a^2-b^2}+frac{b^2}{a^2-b^2}})=frac{2a^2+2b^2}{a^2-b^2}*frac{a^2-b^2}{a^2+b^2}=$

$=frac{2(a^2+b^2)}{a^2+b^2}=2$

 

$(frac{x^2y-xy^2}{x-y}+xy)(frac{y}{x}+frac{x}{y})=frac{x^2y-xy^2+x^2y+xy^2}{x-y}*frac{y^2+x^2}{xy}=frac{2x^2y}{x-y}*frac{y^2+x^2}{xy}$

$frac{2x^2y}{x-y}*frac{y^2+x^2}{xy}=frac{2x(y^2+x^2)}{x-y}$

 

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