Question

2sin2x*cos2x=1

Answer 1

$sin4x=1. 4x=pi/2+2pi*n. x=pi/8+pi*n/2.$

Answer 2

2sin2x*cos2x=1 4sin2x*cos2x=2 2sin4x=2 sin2x=1 2x=пи/2 + 2пи*эн х=пи/4 +пи/2*н