Question

(x+1)(3x+1)=5 решить уравнение

Answer 1

исходное не пишу
3х²+3х+х+1=5
3х²+4х-4=0
D=16+48=64=8²
х₁=(-4+8)/6=2/3
х₂=(-4-8)/6=-2

Answer 2

$(x+1)(3x+1)=5 3 x^{2} +x+3x+1=5 3 x^{2} +4x-4=0 D= b^{2} -4ac D= 4^{2} -4*3*(-4)=64 x_{1} = frac{-b+ sqrt{D} }{2a} = frac{-4+8}{6} = -frac{2}{3} x_{2}= frac{-b- sqrt{D} }{2a} = frac{-4-8}{6} = -2$