Question

Пожалуйста, помогите решить.
b2-64/4b+23 + 8(b-8)/b+8=

Answer 1

(b-8)(b+8)/(4b+23)+8(b-8)/(b+8)=[(b-8)(b+8)²+8(b-8)(4b+23)]/(b+8)(4b+23)=
=(b-8)(b²+16b+64+32b+184)/(b+8)(4b+23)=
=(b-8)(b²+48b+248)/(b+8)(4b+23)