Question

Решите уравнение под номером 3

Answer 1

x²+x-12=0
x1=x2=-1 U x1*x2=-12
1)3/(x+4)+6x/[(x-3)(x+4)]-1/(x-3)=(3x-9+6x-x-4)/[(x+4)(x-3)]=(8x-13)/[(x+4)(x-3)]
2)(8x-13)/[(x+4)(x-3)]*(x-4)(x+4)/(8x-13)=(x-4)/(x-3)