Question

Решите пожалуйста))!!!

$14^{x}+7= 2^{x} +7^{x+1}$

Answer 1

Решение
14^x + 7 = 2^x + 7^(x + 1)
(2^x)*(7^x) + 7 - (2^x) - (7^x)*7 = 0
(7^x)*(2^x - 7) - (2^x - 7) = 0
(2^x  - 7)*(7^x - 1) = 0
1)  2^x - 7 = 0
3^x = 7
log₃ (3^x) = log₃ 7
x₁ = log₃ 7
2)  7^x - 1 = 0
7^x = 1
7^x = 7⁰
x₂ = 0