Question

Как решить эту систему?

Answer 1

2x^2+4y^2=24 |*2
4x^2+8y^2=24x

4x^2+8x^2=48
4x^2+8x^2=24x

48-24x=0
-24x=-48
x=2
2*2^2+4y^2=24
2*4+4y^2=24
8+4y^2=24
4y^2=24-8
4y^2=16
y^2=4
y=2
Ответ:(2;2)