Question

ПОМОГИТЕ ААААААА ОРУ СЛОЖНА

Answer 1

$lim_{x to infty} frac{6x^2+5x+4}{8x^2+4x+1}= lim_{x to infty} frac{ frac{6x^2}{x^2}+ frac{5x}{x^2}+ frac{4}{x^2}}{ frac{8x^2}{x^2}+ frac{4x}{x^2}+ frac{1}{x^2}}= \ \ = lim_{x to infty} frac{6+ frac{5}{x}+ frac{4}{x^2}}{8+ frac{4}{x}+ frac{1}{x^2} }= frac{6}{8}= frac{3}{4}$

Ответ: 3/4

Answer 2

lim(6x^2+5x+4)/(8x^2+4x+1)=lim(6+5/x+4/x^2)/(8+4/x+1/x^2)=6/8=3/4    [ /x^2]