Question

Помогите...................

Answer 1

256-16•22+0,255•484=25

Answer 2

$x^{2} + xy + 0.25y^2 = x^2 + 2*x(0,5y) + (0.5y)^2 = (x + 0.5y)^2$
подставим x и y:
$(-16 + 22*0,5)^2 = (11-16)^2 = (-5)^2 = 25$
Ответ: 1