Question

корень квадратный 3 sin (-П/3)-2ctg(-п/4)+4cos(-3/2)п

Answer 1

sin(-pí/3)=-sin pí/2 = -V3/2
cotg(-pí/4)=-cotg(pí/4)=-1
cos(-3pí/2=cos(3pí/2)=0,V3.(-V3/2 -2.(-1)+4.0=-3/2+2=-3/2+4/2=1/2