Question

Упростите
48k-12k²+k³-64

Answer 1

48k-12kˇ2+kˇ3-64=12k(4-k) +(kˇ3-4ˇ3)=
=12k(4-k)-(4ˇ3-kˇ3)=12k(4-k)-(4-k)(4ˇ2+4k+kˇ2)=
=(4-k)(12k-16-4k-kˇ2)=(4-k)(-kˇ2+8k-16)=
=(k-4)(kˇ2-8k+16)=(k-4)(k-4)ˇ2=(k-4)ˇ3