Question

log(2)3log(3)5log(5)6log(6)8=

Answer 1

$log_23cdot log_35cdot log_56cdot log_68= frac{log_35}{log_32}cdot frac{log_68}{log_65}=\\=log_25cdot log_58=frac{log_58}{log_52}=log_28=log_22^3=3\\\Formyla:; ; log_{a}{b}=frac{log_{c}b}{log_{c}a}; ; Rightarrow; ; frac{log_{c}b}{log_{c}a}=log_ab$