Question

Корень(3x+1)-корень(1-x)=1

Answer 1

ОДЗ
3x+1≥0⇒x≥-1/3
1-x≥0⇒x≤1
x∈[-1/3;1]
√(3x+1)=1+√(1-x)
3x+1=1+2√(1-x)+1-x
2√(1-x)=4x-1
4(1-x)=16x²-8x+1
16x²-8x+1-4+4x=0
16x²-4x-3=0
D=16+192=208
x1=(4-4√13)/32=(1-√13)/4
x2=(1+√13)/4