Question

(12y+18)(1,6-9,2y)=0

Answer 1

(12y+18)(1,6-9,2y)=0

1) 12y+18=0

12y=-18

y1=-1,5

2) 1,6-9,2y=0

9,2y=1,6

y=92/16=23/4=5,75